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1. Create a tuple that contains 0, 0, 1, 0, 1, and 1
2. Count the number of 0 using a method.
3. Find the index of the first 1 using a method.
4. Delete the tuple.
Tips: To delete a tuple, you could use del followed by the tuple name.

Right Answer:

# Step 1 binary_tuple = (0, 0, 1, 0, 1, 1) # Step 2 count_zeros = binary_tuple.count(0) print(count_zeros) # Output: 3 # Step 3 index_of_first_one = binary_tuple.index(1) print(index_of_first_one) # Output: 2 # Step 4 del binary_tuple # Deleting the tuple

1. Create a list named fishes that contains “catfish”, “perch”, “cod” and “carp”
2. Show the last element of the list using two different ways.
3. Change the second element of the list by another fish name.
4. Print the modified list.

Right Answer:

# Step 1 fishes = ["catfish", "perch", "cod", "carp"] # Step 2 print(fishes[-1]) # Output: carp (using negative index) print(fishes[3]) # Output: carp (using positive index) # Step 3 fishes[1] = "salmon" # Changing the second element to "salmon" # Step 4 print(fishes) # Output: ['catfish', 'salmon', 'cod', 'carp']

1. Create a list named mylist that contains ‘abc’, False, 1 and 3.14159.
2. Change False and 1 to True and 0 in one operation.
3. Extract the element ‘abc’ from the list and assign it to a variable in one operation.
4. Print that variable.
5. Assign the 3 list elements into 3 variables in one operation.
6. Print these variables.

Right Answer:

# Step 1 mylist = ['abc', False, 1, 3.14159] # Step 2 mylist[1:3] = [True, 0] # Change False and 1 to True and 0 # Step 3 abc_var = mylist.pop(0) # Extract 'abc' and assign it to abc_var print(abc_var) # Output: 'abc' # Step 4 var1, var2, var3 = mylist # Assign the remaining list elements to variables # Step 5 print(var1, var2, var3) # Output: True, 0, 3.14159

1. Given a list named days that contains "Monday", "Tuesday", "Wendesday",
"Thursday" and "Friday".
2. Correct the typo in "Wendesday" to "Wednesday" using the days list.
3. Print the list to ensure the change has been made.

Right Answer:

# Step 1 days = ["Monday", "Tuesday", "Wendesday", "Thursday", "Friday"] # Step 2 days[2] = "Wednesday" # Correcting the typo # Step 3 print(days) # Output: ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday']

1. Create a list named integers that contains 0, 1 and 3.
2. Add the number 4 to the end of the list using two different methods.
3. Add the number 2 in the list at the correct index to get a sequence.
4. Print the list, it should display 0, 1, 2, 3, 4.
5. Create a new list that contains 5, 6, 7 and 8.
6. Add this new list at the end of the integers list.
7. Remove the number 0 from the list.

Right Answer:

# Step 1 integers = [0, 1, 3] # Step 2 integers.append(4) # Method 1: Using append() integers += [4] # Method 2: Using += operator # Step 3 integers.insert(2, 2) # Insert 2 at the correct index to create a sequence # Step 4 print(integers) # Output: [0, 1, 2, 3, 4] # Step 5 new_list = [5, 6, 7, 8] # Step 6 integers.extend(new_list) # Adding the new list at the end of the integers list # Step 7 integers.remove(0) # Removing the number 0 from the list print(integers) # Output: [1, 2, 3, 4, 5, 6, 7, 8]

1. Ask the user to provide three numerical inputs.
2. Create a tuple out of them.
3. If the sum of the first and second elements of the tuple is greater than the third, print
the tuple in reverse.
4. Otherwise, print the tuple normally.

Right Answer:

# Step 1 num1 = float(input("Enter first number: ")) num2 = float(input("Enter second number: ")) num3 = float(input("Enter third number: ")) # Step 2 num_tuple = (num1, num2, num3) # Step 3 and Step 4 if num1 + num2 > num3: print(num_tuple[::-1]) # Print the tuple in reverse else: print(num_tuple) # Print the tuple normally

1. Given a list named animals that contains "cat", "dog" and “apple”
2. Remove the “apple” from the list.
3. Print the list.
4. Add "rabbit" to the list.
5. Print the list.

Right Answer:

# Step 1 animals = ["cat", "dog", "apple"] # Step 2 animals.remove("apple") # Removing "apple" from the list # Step 3 print(animals) # Output: ['cat', 'dog'] # Step 4 animals.append("rabbit") # Adding "rabbit" to the list # Step 5 print(animals) # Output: ['cat', 'dog', 'rabbit']

1. Given a tuple named months that contains "Jan", "Feb", "Mach” and "Apr"
2. Try to correct the typo in "Mach" to "March".
3. What happens?
4. Convert the tuple into a list.
5. Retry to correct the typo in "Mach" to "March".
6. Convert the list into a tuple.
7. Print the tuple.

Right Answer:

# Step 1 months = ("Jan", "Feb", "Mach", "Apr") # Step 2 # Trying to correct the typo will raise an error as tuples are immutable. # Step 3 - Explanation # Tuples are immutable, meaning we cannot change their items directly. # Step 4 months_list = list(months) # Converting tuple to list # Step 5 months_list[2] = "March" # Correcting the typo # Step 6 months = tuple(months_list) # Converting the list back to a tuple # Step 7 print(months) # Output: ('Jan', 'Feb', 'March', 'Apr')

1. Create a list named values that contains 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10.
2. Slice the list such that you get every second element starting from the end, but not
including the last element.
3. Print the result (it should be 9, 7, 5, 3, 1).

Right Answer:

# Step 1 values = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # Step 2 sliced_values = values[-2::-2] # Slice to get every second element from the end, excluding the last element # Step 3 print(sliced_values) # Output: [9, 7, 5, 3, 1]

1. Create a list named floats that contains 1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7 and 8.8
2. Use slicing to get the elements 2.2, 3.3 and 4.4 in one operation.
3. Use slicing to get the elements from 3.3 to the end of the list.
4. Use slicing to get the elements from the start of the list to 5.5 included.
5. Use slicing to reverse the list.

Right Answer:

# Step 1 floats = [1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8] # Step 2 print(floats[1:4]) # Output: [2.2, 3.3, 4.4] # Step 3 print(floats[2:]) # Output: [3.3, 4.4, 5.5, 6.6, 7.7, 8.8] # Step 4 print(floats[:5]) # Output: [1.1, 2.2, 3.3, 4.4, 5.5] # Step 5 print(floats[::-1]) # Output: [8.8, 7.7, 6.6, 5.5, 4.4, 3.3, 2.2, 1.1]

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